Q. 419

Question

The church youth group is

selling snacks to raise money to

attend their convention. Amy sold

2 pounds of candy, 3 boxes of

cookies and 1 can of popcorn for

a total sales of \(65. Brian sold 4

pounds of candy, 6 boxes of

cookies and 3 cans of popcorn for

a total sales of \)140. Paulina sold

8 pounds of candy, 8 boxes of

cookies and 5 can of popcorn for a

total sales of $250. What is the cost

of each item?

Step-by-Step Solution

Verified
Answer

The cost of candies is 20$, cost of boxes of cookies is 5$and that of popcorn is 10$.

1Step 1. Given information.

Amy sold:

2 pound of candies, 3 boxes of cookies and 1 can of popcorn.

Brian sold:

4 pounds of candy, 6 boxes of

cookies and 3 cans of popcorn.

Paulina sold :

8 pounds of candy, 8 boxes of

cookies and 5 can of popcorn.

Their total worth are:

65$140$250$


2Step 2. Write the concept.

Let the price of candies be x$,price of cookies be y$ and price of popcorn be z$.

Therefore equation framed will be:

2x+3y+z=65 ........(1)4x+6y+3z=140 .....(2)8x+8y+5z=250 ......(3)

3Step 3. Calculation.

2x+3y+z=65 ........(1)4x+6y+3z=140 .....(2)8x+8y+5z=250 ......(3)Multiplying 2 with equation (1) and subtracting with equation (2) we get:Solve for z:(4x+6y+3z)-(4x_6y-2z)=140-130z=10Now substituting value of z in eq(1) and (2)2x+3y=55 ..........(3)4x+6y=110 .........(4)Solve for y:considering eq(3) and eq(1) we get2x+3y=558x+8y=200Multiplying 2 with eq(3) and subtracting with eq(4) we get:(8x+12y)-(8x+8y)=220-2004y=20y=5Solve for x:put the values of x,y and z in eq(1)2x+3(5)+10=65x=20

4Step 4. Check the values.

Substitute all values of x,y and z in equation 2x+3y+z=65.

We get:

2(20)+3(5)+10=6565=65

which holds true.