Q. 411 - Intermediate Algebra

Question

In the following exercises, factor completely

$64j^2+225$.

Step-by-Step Solution

Answer

The expression is a sum of squares of numbers and not a factor.

${\left(8j\right)}^2+{\left(15\right)}^2$

Step 1. Given and explanation

We have $64j^2+225$.

We can see that this forms a pattern of sum of squares of numbers.

Step 2. Write the concept

For factoring we use the formula:

$a^2-b^2=(a+b)(a-b)$

Step 3. Calculation

The above-mentioned formula can't be applied here as the given expression is the sum of the square of numbers i.e

$$\begin{gathered} 64j^2+225 \\ ={\left(8j\right)}^2+{\left(15\right)}^2 \end{gathered}$$

Therefore, sum of squares do not factor.