Q. 41 - Calculus

Question

Integral Formulas: Fill in the blanks to complete each of the following integration formulas.

$\int \frac{1}{1-x^2}dx=............$

Step-by-Step Solution

Answer

The value of $\int \frac{1}{1-x^2}dx=\tan h^{-1}x+C$.

Step 1. Given information .

Consider the given integral function $\int \frac{1}{1-x^2}dx$ .

Step 2. Fill the blank for ∫ 1 1 - x 2 d x .

The integral of the basic function $\int \frac{1}{1-x^2}dx=\tan h^{-1}x+C$ .