Q. 41

Question

In Exercises 31–52, find the relative maxima, relative minima, and saddle points for the given functions. Determine whether the function has an absolute maximum or absolute minimum as well. f(x,y)=x sin y

Step-by-Step Solution

Verified
Answer

The points (0, nπ) where, n is an integer, are all saddle points.

1Step 1. Given information

A function, f(x,y)=x sin y

2Step 2. Finding the first-order, second-order partial derivatives and determinant of hessian

The first-order partial derivatives of the function are:fx(x,y)=fx=sin y and fy(x,y)=fy=x cos yNow, solve the system of equations: sin y=0 and x cos y=0, we get,x=0 and y=nπ where, n is an integerStationary points of f are: (0, nπ)The second-order partial derivatives of the function are:fxx(x,y)=2fx2=0, fyy(x,y)=2fy2=-x sin y and fxy(x,y)=2fxy=cos yfxx(0, nπ)=0, fyy(0, nπ)=0 and fxy(0, nπ)=±1The determinant of the Hessian is:detHfx,y=2fx22fy2-2fxy2detHf0,nπ=0×0-±12=-1

3Step 3. Testing and finding relative maximum, relative minimum and saddle points

If f has a stationary point at (x0,y0), then (a)  f has a relative maximum at (x0,y0) if det(Hf(x0,y0))>0 with fxx(x0,y0)<0 or fyy(x0,y0)<0. (b) f has a relative minimum at (x0,y0) if det(Hf(x0,y0))>0 with fxx(x0,y0)>0 or fyy(x0,y0)>0. (c) f has a saddle point at (x0,y0) if det(Hf(x0,y0))<0. (d) If det(Hf(x0,y0))=0, no conclusion may be drawn about the behavior of f at (x0,y0).In the given function, detHf0, nπ=-1<0 Hence, the given function has saddle points at 0, nπ.

4Step 4. Testing and finding absolute maximum and absolute minimum

There are no absolute maximum and minimum points.