Q. 40 - Calculus

Question

If ${\int }_{-2}^{3}f\left(x\right)dx=4,{\int }_{-2}^{6}f\left(x\right)dx=9,{\int }_{-2}^{3}g\left(x\right)dx=2$, and ${\int }_3^{6}g\left(x\right)dx=3$, then find the values of each definite integral in Exercises $29-40$. If there is not enough information, explain why.

${\int }_{-2}^{-2}x\left(f\right(x)+3{)}^{2}dx$

Step-by-Step Solution

Answer

The value of definite integral cannot be found as there is not enough information. 

Step 1. Given Information

We are given,

${\int }_{-2}^{-2}x\left(f\right(x)+3{)}^{2}dx$

Step 2. Finding the Integral

The definite integral cannot be found out as there is not enough information available. Therefore, the value is not possible to find.