Q 4. - Precalculus Enhanced with Graphing Utilities

Question

Use a graphing utility to approximate the real solution of equation rounded to two decimal place . All solution lie between $-10$ and $10$.

Equation is $2x^3-x^2-2x+1=0$.

Step-by-Step Solution

Answer

The root of the given equation are $\frac{1}{2} ,\pm 1$.The graph is shown below.

Ste[p 1. Given information.

Consider the given equation .$2x^3-x^2-2x+1=0$

Step 2. Find the root of the given equation.

To find the root of the equation simplify the given equation.

$$\begin{gathered} x^2\left(2x-1\right)-1\left(2x-1\right) \\ \left(2x-1\right)=0 ,\left(x^2-1\right)=0 \\ x=\frac{1}{2} ,x=\pm 1 \end{gathered}$$

Step 3. Plot the graph.

The graph of the given equation using graphic utility as shown below.

Equation $2x^3-x^2-2x+1=0$.