Q. 36 - Precalculus Enhanced with Graphing Utilities

Question

The reduced row echelon form of a system of linear equations is given. Write the system of equations corresponding to the given matrix. Use x, y; or x, y, z; or x1, x2, x3, x4 as variables. Determine whether the system is consistent or inconsistent. If it is consistent, give the solution.  

$\left[\begin{array}{ccccc}1& 0& 0& 0|& 1\\ 0& 1& 0& 0|& 2\\ 0& 0& 1& 0|& 3\\ 0& 0& 0& 1|& 0\end{array}\right]$

Step-by-Step Solution

Answer

The system of equation is $x=1,y=2,z=3,w=0$ and the system is consistent and the solution set is  $x=1,y=2,z=3,w=0$

Step 1. Given Information

The given matrix is 

$\left[\begin{array}{ccccc}1& 0& 0& 0|& 1\\ 0& 1& 0& 0|& 2\\ 0& 0& 1& 0|& 3\\ 0& 0& 0& 1|& 0\end{array}\right]$

Step 2. Explanation

The given matrix has four rows. So, it represents a system of four linear equations. The 4 columns to the left of vertical bar indicate that the system has four variables.

Let the variables be x, y, z and w. Then system of linear equation corresponding to the given matrix is as follows,

$$\begin{gathered} x=1, \\ y=2, \\ z=3, \\ w=0 \end{gathered}$$

Step 3. Explanation

A system of linear equation is said to be consistent when it has at least one solution otherwise it is inconsistent.

There is no row and column with all the entries as 0 in the above system of equation. Thus, the system is consistent and the solution set is

$$\begin{gathered} x=1, \\ y=2, \\ z=3, \\ w=0 \end{gathered}$$