Q. 340 - Intermediate Algebra

Question

In the following exercises, solve the systems of equations by substitution.  

$\left\{\begin{array}{l}y=-5x\\ 5x+y=6\end{array}\right.$

Step-by-Step Solution

Answer

The system of linear equations has no solutions.

Step 1. Given information.

The system of linear equations,  

$\left\{\begin{array}{l}y=-5x\\ 5x+y=6\end{array}\right.$

Step 2. Substituting the value of y from one equation into another equation.

$y=-5x$

Now substituting this in another equation we get  

$$\begin{gathered} 5x-5x=6 \\ 0=6 \end{gathered}$$

Therefore the system of linear equations has no solutions.