Q. 34 - Intermediate Algebra

Question

Solve the systems of equations by substitution.

$\left\{\begin{array}{l}5x-2y=-6\\ y=3x+3\end{array}\right.$

Step-by-Step Solution

Answer

The solution of system of linear equation is $(0,3)$

Step 1. Given information

The system of equations is $\left\{\begin{array}{l}5x-2y=-6\\ y=3x+3\end{array}\right.$

Step 2. Substitute the value of y from one equation into other equation

$y=3x+3$

Now,

$$\begin{gathered} 5x-2y=-6 \\ 5x-2(3x+3)=-6 \\ 5x-6x-6=-6 \\ -x=0 \\ x=0 \end{gathered}$$

Step 3. Substitute the value of x in any equation

$$\begin{gathered} y=3x+3 \\ y=3\left(0\right)+3 \\ y=3 \end{gathered}$$

Step 4. Required answer

The solution of system of linear equation is $(0,3)$