Q. 34 - Calculus

Question

Calculate each of the limits in Exercises $29-70$.

$\underset{x\to -2}{\lim }\frac{4+2x}{x+2}$.

Step-by-Step Solution

Answer

The value of $\underset{x\to -2}{\lim }\frac{4+2x}{x+2}$ is, $2$.

Step 1 . Given information

$\underset{x\to -2}{\lim }\frac{4+2x}{x+2}$.

Step 2 . The limit is calculated as below:

$$\begin{gathered} \underset{x\to -2}{\lim }\frac{4+2x}{x+2}=\underset{x\to -2}{\lim }\frac{2\left(x+2\right)}{(x+2)} \\ =\underset{x\to -2}{\lim } 2 \\ =2 \end{gathered}$$