Q. 33 - Precalculus Enhanced with Graphing Utilities

Question

In Problems 31–36, graph each function using the techniques of shifting, compressing or stretching, and reflections. Identify any intercepts on the graph. State the domain and, based on the graph, find the range. 

$h\left(x\right)=\sqrt{x-1}$

Step-by-Step Solution

Answer

The domain of the function is $\left\{x\right|x\ge 1\} or [1,\infty ).$

The intercept is $(1,0).$

The range of the function is $\left\{y\right|y\ge 0\} or [0,\infty ).$

The graph of the function is

Step 1. Given Information

The given function is $h\left(x\right)=\sqrt{x-1}.$

We have to graph the function using the techniques of shifting, compressing, or stretching, and reflections then find the domain, intercepts, and range.

Step 2. Sketching the graph of the function

The basic function of the given function is $f\left(x\right)=\sqrt{x}$

To obtain the graph of h(x) from the graph of basic function, shift the graph of basic function horizontally to the right by $1$ unit.

The graph of h(x) will be identical to the graph of basic function, except that it is horizontally shifted to the right by one unit.

Step 3. Graph of the function

Step 4. Finding the domain of the function

The domain of the function is the set of all possible values of x.

Thus, the domain of the function is $\left\{x\right|x\ge 1\} or [1,\infty ).$

Step 5. Identifying the intercepts

The points where a line crosses the x-axis and the y–axis are called the intercepts.

Thus, the graph touches the axis at $(1,0).$

Step 6. Finding the range

From the graph, we conclude that y-coordinates are between 

$0 and \infty .$

Thus, the range is $\left\{y\right|y\ge 0\} or [0,\infty ).$