Q. 325 - Intermediate Algebra

Question

In the following exercises, solve.

$\sqrt{8+2r}=\sqrt{3r+10}$

Step-by-Step Solution

Answer

The solution of the given equation is $r=-2$.

Step 1. Given information.

The given equation is:

$\sqrt{8+2r}=\sqrt{3r+10}$

Step 2. Solve the equation.

Take square on both sides.

$\begin{array}{rcl}(\sqrt{8+2r}{)}^2& =& (\sqrt{3r+10}{)}^2\\ 8+2r& =& 3r+10\\ 8-10& =& 3r-2r\\ -2& =& r\end{array}$

Step 3. Conclusion.

The solution of the given equation is $r=-2$.