Q. 3.20 - An Introduction to General, Organic, and Biological Chemistry

Question

a. Water is healed to ${145}^{\circ }F$. What is the temperature of the hot water in degrees Celsius?

b. During extreme Hypothermia, a child's temperature dropped to ${20}^{\circ }C$. What was his temperature in degrees Fahrenheit?

Step-by-Step Solution

Answer

a. The temperature in degrees Celsius is $62.7°C$

b. The temperature in degrees Fahrenheit is $217.4°F$

Step 1: Given Information (a)

(a) Water is healed to $145°F$

Step 2: Explanation (a)

(a) Hot water temperature in Fahrenheit is $145°F$.
The temperature scale and Fahrenheit scale are related as follows: 

$F=\frac{9}{5}\left(C\right)+32$

Substitute the worth of degree Fahrenheit to search out the worth in degree. 

${}^{\circ }\mathrm{C}=\frac{5}{9}\left({}^{\circ }\mathrm{F}-32\right)$

$=\frac{5}{9}\left({145}^{\circ }\mathrm{F}-32\right)$

$=\frac{5}{9}(113{)}^0\mathrm{C}$

$={62.7}^{\circ }\mathrm{C}$

Thus, the temperature $145°F$ is adore the temperature $62.7°C$ .

Step 3: Given Information (b)

Extreme Hypothermia Child's temperature dropped to $20°C$

Step 4: Explanation (b)

(b) Body temperature in degree Centigrade is $20.6°C$
The relationship between temperature scale and Celsius scale is as follows: 

$F=\frac{9}{5}\left(C\right)+32$

Substitute the worth of degree Celsius to seek out the worth in Fahrenheit. 

$F=\frac{9}{5}\left(C\right)+32$

$=\frac{9}{5}\left(20.6\mathrm{C}\right)+32$

$=185.4+32$

$=217.4°F$

Thus, the temperature $20.6°C$ is reminiscent of the temperature $217.4°F$.