Q. 32

Question

In Exercises 27–32, (a) determine whether the given subset of R3 is open, closed, both open and closed, or neither open nor closed, (b) find the complement of the set, and (c) find the boundary of the given set.

R3

Step-by-Step Solution

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Answer

Part (a): The set is both open and closed.

Part (b): The compliment of the set is ϕ

Part (c): The boundary of the set is ϕ

1Part (a): Step 1. Given Information

The goal is to figure out if the set R3 is open, closed, open and closed, or neither open nor closed.

2Part (a): Step 2. Identify whether the set is open, closed both, or neither.

Take a look at the following statement (1): Consider the A subset of R3 

Then the subset A of R3 is open for all (x,y,z)R3, if there is an open disc D such that (x,y,z)DA 

Since there exists an open disc D1 for each element (a,b,c)R3 such that (x,y,z)D1R3 . As a result of assertion (1), the set R3 as a subset of R3 is open

Take a look at the second statement: Consider the subset A of R3.

 If its complement, Ac, is open, then the subset A of R3 is closed.

The compliment of the set R3 as subset of R3 is defined as

{R3}C= {(x,y,z)R3|(x,y,z)R3}

As a result, the complement of the set R3, as a subset of R3 is (R3)c=ϕ

As a result of assertion (1), the empty set ϕ is open.

 As a result of assertion (2), the set R3 as a subset of  R3 is closed.

As a result, the set R3 as a subset of R3 is both open and closed.

3Part (b): Step 1. Determine the complement of the set

The goal is to find the complement of the set R3 as a subset of R3. The complement of the set R3 as a subset of R3 is defined as (R3)C={(x,y,z)R3|(x,y,z)R3} 

As a result, the complement of the set R3 as a subset of R3 is (R3)C=ϕ.

4Part (c): Step 1. Determine the boundary of the set.

The goal is to discover the border of set R3 as a subset of R3

Consider the following statement (3):

Consider the subset A of R3.

The point (x,y,z) is said to be a boundary point of A if the open ball in the R3 containing (x,y,z) crosses both A and Ac.

Consider the point (a,b,c)R3

Consider an open ball S1 containing (a,b,c).

As a result, the open ball S1 intersects R3 but not (R3)C=ϕ.

Thus, (a,b,c)R3 is not the border point of set R3.

Because (a,b,c)R3 is arbitrary, the boundary of the set R3 as a subset of R3 is ϕ.