Q. 32
Question
In Exercises 27–32, (a) determine whether the given subset of is open, closed, both open and closed, or neither open nor closed, (b) find the complement of the set, and (c) find the boundary of the given set.
Step-by-Step Solution
VerifiedPart (a): The set is both open and closed.
Part (b): The compliment of the set is
Part (c): The boundary of the set is
The goal is to figure out if the set is open, closed, open and closed, or neither open nor closed.
Take a look at the following statement (1): Consider the A subset of
Then the subset A of is open for all , if there is an open disc D such that
Since there exists an open disc for each element such that . As a result of assertion (1), the set as a subset of is open
Take a look at the second statement: Consider the subset A of .
If its complement, , is open, then the subset A of is closed.
The compliment of the set as subset of is defined as
As a result, the complement of the set , as a subset of
As a result of assertion (1), the empty set is open.
As a result of assertion (2), the set as a subset of is closed.
As a result, the set as a subset of is both open and closed.
The goal is to find the complement of the set as a subset of . The complement of the set as a subset of is defined as
As a result, the complement of the set as a subset of is .
The goal is to discover the border of set as a subset of
Consider the following statement (3):
Consider the subset A of .
The point is said to be a boundary point of A if the open ball in the containing crosses both .
Consider the point
Consider an open ball containing .
As a result, the open ball intersects but not .
Thus, is not the border point of set .
Because is arbitrary, the boundary of the set as a subset of .