Q. 3

Question

Examples: Construct examples of the thing(s) described in the following. Try to find examples that are different than any in the reading.

  1. The graph of a function f for which f' is positive everywhere, f''(x)>0 for x<-2, and f''(x)<0 for x>-2.
  2. The graph of a function f for which f(3)=0, f'(3)=0, and f''(3)=0.
  3. The graph of a function f for which f(x) is zero at x=-1, x=2, and x=4;f'(x) is zero at x=-1, x=1, and x=3; and f'' is zero at x=0 and x=2.

Step-by-Step Solution

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Answer

Part(a) The example is f(x)=-(x+2)-5.

Part(b) The example isf(x)=(x-3)5

Part(c) It is not given which interval gives a positive result or which interval gives a negative result. Hence it is not possible to sketch such a function.

1Part(a) Step 1. Given Information.

We are given a function f(x) and different conditions.

a. The graph of a function f for which f' is positive everywhere,f''(x)>0 for x<-2, and f'(x)<0 forx>-2.

b. The graph of a function f for which f(3)=0, f'(3)=0, and f''(3)=0.

c. The graph of a function f for which f(x) is zero at x=-1,x=2, and x=4, f'(x) is zero at x=-1,x=1, and x=3, and f'' is zero at x=0 and x=2.

2Part(a) Step 1. Finding the example


The graph of a function f for which f' is positive everywhere, f''(x)>0 for x<-2, and f''(x)<0 for x>-2,

Let the function be,

f(x)=-(x+2)-5

The graph is as follows,


3Part(a) Step 1. Checking the derivative

The derivative is given by,

f'(x)=-(-5)(x+2)-5-1=5(x+2)-6=5(x+2)6

And,

f''(x)=ddx5(x+2)-6=5(-6)(x+2)-6-1=-30(x+2)-7

Hence, the example is f(x)=(x+2)5 .

4Part (b) Step 1. Finding example


The graph of a function f for whichf(3)=0,f(3)=0 andf′′(3)=0

Let the function be f(x)=(x3)5

The graph is as follows,


5Part(b) Step 2. Checking the derivative

The derivative is given by,

f(x)=5(x3)51=5(x3)4

And

f′′(x)=5(4(x3)41)=20(x3)3

Hence the function isf(x)=(x3)5

6Part (c) Step 1. Finding example

The graph of a function f for which f(x) is zero at x=-1,x=2 and x=4, f'(x) is zero at x=-1,x=1 and x=3; and f''(x) is zero at x=0 and x=2.


Here, it is not given that which interval gives a positive result or which interval gives a negative result. Hence it is not possible to sketch such a function.