Q. 299 - Intermediate Algebra

Question

Divide polynomial by monomial-

$\left(48y^4-24y^3\right)÷\left(-8y^2\right)$

Step-by-Step Solution

Answer

The solution is, $-6y^2+3y$

Step 1. Given information

To solve,

$\left(48y^4-24y^3\right)÷\left(-8y^2\right)$

Step 2. Calculation

Solving the equation,

$\left(48y^4-24y^3\right)÷\left(-8y^2\right)$

$$\begin{gathered} =\frac{\left(48y^4-24y^3\right)}{\left(-8y^2\right)} \\ =\frac{48y^4}{-8y^2}-\frac{24y^3}{-8y^2} \\ =-6y^2+3y \end{gathered}$$

The solution is $-6y^2+3y$