Q. 2.98 - An Introduction to General, Organic, and Biological Chemistry

Question

A fish company delivers $22 \mathrm{kg}$ of salmon, $5.5 \mathrm{kg}$ of crab, and $3.48 \mathrm{kg}$ of oysters to your seafood restaurant. (2.3,2.6 )

a. What is the total mass, in kilograms, of the seafood?

b. What is the total number of pounds?

Step-by-Step Solution

Answer

a) The total mass of the seafood in kilograms is determined as $31 kg$

b) The total number of pounds is determined as $68 pounds$

Step 1 : Introduction (part a)

The given is the weights of the Salmon, crab, and oyster 

The objective is to determine the total mass of seafood and total number of pounds

Step 2 : Explanation (part a)

(a) Mass of salmon $=22 \mathrm{kg}$ (zero decimal places)

Mass of crab $=5.5 kg$(one decimal place)

Mass of oysters $=3.48 \mathrm{kg}$ (two decimal places)

$Total mass of seafood = Mass of salmon + Mass of Crab + Mass of oysters.$

$$\begin{gathered} =22 kg+5.5 kg+3.48 kg \\ =30.98 kg \end{gathered}$$

We must round off to zero decimal places because the least number of decimal places is zero., Since $9\ge 5$, we add 1 to zero giving $31 \mathrm{kg}$

Step 3 : Introduction (part b)

The given is the weights of the Salmon, crab, and oyster 

The objective is to determine the total mass of seafood and total number of pounds 

Step 4 : Explanation (part b)

(b)

As $1 \mathrm{kg}=2.20$ pounds

So $31 kg=31\times 2.20 pounds =68.2$ pounds

$31$ has $2$ signiflcant flgures

$2.20$ has $3$ signiflcant flgures

So rounding off to $2$ significant figures (least number) gives us $68$ pounds