Q. 27

Question

Solve each of the integrals in Exercises 21–70. Some integrals require substitution, and some do not. (Exercise 69 involves a hyperbolic function.) 

xcsc2x2dx

Step-by-Step Solution

Verified
Answer

The solution of the given integral is xcsc2x2dx=-12cotx2+C.

1Step 1. Given Information

Solving the given integrals. 

xcsc2x2dx

2Step 2. Solving the given integral using substitution method.

Let 

u=x2dudx=2xdu=2xdx12du=xdx

3Step 3. This substitution changes the integral into

xcsc2x2dx=12csc2uduxcsc2x2dx=12-cotu+Cxcsc2x2dx=12-cotx2+Cxcsc2x2dx=-12cotx2+C