Q. 26

Question


Consider the region between f(x) = x and the x-axis on [0, 4]. For each line of rotation given in Exercises 25–28, use four shells based on the given rectangles to approximate the volume of the resulting solid.



Step-by-Step Solution

Verified
Answer

The volume of solid formed is 79.742

1Step 1: Given information

The figure is 

2Step 2: Calculation

As the solid is rotated around the $y$-axis so the rectangles are drawn parallel to the $y$-axis, that is shells with base on the $x$-axis. On the $x$-axis the interval $[0,4]$ is divided into four subintervals viz $[0,1],[1,2],[2,3]$ and $[3,4]$, the width of each subinterval is 1 that is $\Delta x=1$. Since the region in the diagram is bounded by $f(x)=\sqrt{x}$, so height of the shells is given by $h=\sqrt{x}$

For the first shell on the interval $[0,1]$, the radius of the shell is the midpoint of $[0,1]$ that is $0.5$ also the height of the shell is found at the midpoint of $[0,1]$, that is $h=\sqrt{0.5}=0.707$

Hence volume of first shell is

$$

\begin{aligned}

2 \pi r h \Delta x &=2 \pi(0.5)(0.7071)(1) \\

&=2.221

\end{aligned}

$$

Volume of first shell is $2.221$

The second shell has the average radius equal to the midpoint of $[1,2]$ that is $1.5$ and its height computed at the midpoint is $h=\sqrt{1.5}=1.2247$

So the volume of the second shell is

$$

\begin{aligned}

2 \pi r h \Delta x &=2 \pi(1.5)(1.2247)(1) \\

&=11.543

\end{aligned}

$$

Volume of second shell is $11.543$


3Step 3: Further calculation

The third shell has the average radius equal to the midpoint of $[2,3]$ that is $2.5$ and its height computed at the midpoint is $h=\sqrt{2.5}=1.5811$

So the volume of the third shell is

$$

\begin{aligned}

2 \pi r h \Delta x &=2 \pi(2.5)(1.5811)(1) \\

&=24.836

\end{aligned}

$$

Volume of third shell is $24.836$

The fourth shell has the average radius equal to the midpoint of $[3,4]$ that is $3.5$ and its height computed at the midpoint is $h=\sqrt{3.5}=1.8708$,

So the volume of the third shell is

$$

\begin{aligned}

2 \pi r h \Delta x &=2 \pi(3.5)(1.8708)(1) \\

&=41.142

\end{aligned}

$$

Volume of fourth shell is $41.142$

Therefore, the volume of solid formed is 2.221+11.543+24.836+41.142=79.742