Q. 26

Question

a. Find the slopes of OD¯ andNF¯ .

b. Why is ΔOCDΔNEF? 

c.  Why is DOCFNE?

d.  Why isOD¯NF¯ ?

e. What do you think is true about the slopes of parallel lines?


Step-by-Step Solution

Verified
Answer
  1. The slope ofOD¯ andNF¯ is (1).
  2. ΔOCDΔNEFby SAS rule.
  3. OD¯and NF¯ have the same angle with thex-axis .
  4. The lineOD¯ is parallel to the lineNF¯ .
  5. The slope of the parallel lines is the same.
1Part a. Step-1 – Given

Given figure is:

2Step-2 – To determine

We have to find the slopes ofOD¯ andNF¯ .

3Step-3 – Calculation

In the figure (1):

Given coordinates ofOD are (0, 0) and (3, 3).

We have to calculate the slope of the line:

m=y2y1x2x1

Substituting the values in the formula of slope forOD¯ .

m=3030m=33m=1

Given that the coordinates of NF¯are (5, 0) and (8, 3).

We will calculate the slope ofNF¯ .

m=3085m=33m=1

So, the slope ofOD¯ andNF¯ is 1.

4Part b. Step-1 – Given

Given figure is:

5Step-2 – To determine

We have to show that ΔOCDΔNEF.

6Step-3 – Calculation

In ΔOCD and ΔNEF in the given figure:

OC¯=NE¯CD¯=EF¯C=E90o

So, ΔOCDΔNEF

Hence, ΔOCDΔNEF by SAS rule.

7Part c. Step-1 – Given

Given figure is:

8Step-2 – To determine

We have to show that DOCFNE.

9Step-3 – Calculation

From the given figure:

The slope ofOD¯ is equal to the slope ofNF¯

So,tanDOC=tanFNE

Hence, DOCFNE.

10Part d. Step-1 – Given

Given figure is:

11Step-2 – To determine

We have to find why OD¯NF¯.

12Step-3 – Calculation

In the given figure:

We see thatOD¯ and NF¯ have the same angle with the , and it is also evident from the above solution.

tanDOC=tanFNE

It means OD¯NF¯

So, OD¯NF¯

13Part e. Step-1 – Given

Given figure is:

14Step-2 – To determine

We have to find the slope of parallel lines.

15Step-3 – Calculation

In the given figure,

The parallel lines have the same angle with the .

So, the slopes of the parallel lines are the same.