Q. 2.49 - An Introduction to General, Organic, and Biological Chemistry | StudyQuestionHub

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Q. 2.49

Question

Write the equality and two conversion factors, and identify the numbers as exact or give the number of significant figures for each of the following:
a. A bee flies at an average speed of $3.5 m$ per second.
b. The Daily Value (DV) for potassium is $3.5 g$ .
c. An automobile traveled $2.60 k m$ on $1 L$ of gasoline.
d. Silicon makes up $28.2 %$ by mass of Earth's crust.

Step-by-Step Solution

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Answer

Part(a) The equality and conversation factors are $1 s = 3.5 m$ , $\frac{1 s}{3.5 m}$ and $\frac{3.5 m}{1 s}$ There are two significant and one exact numbers.

Part(b) The equality and conversation factors are $1 D V = 3.5 g$ , $\frac{1 D V}{3.5 g}$ and $\frac{3.5 g}{1 D V}$ There are two significant and one exact numbers.

Part(c) The equality and conversation factors are $1 L = 2.6 k m$ , $\frac{1 L}{2.6 k m}$ and $\frac{2.6 k m}{1 L}$ There are two significant and one exact numbers.

Part(d) The equality and conversation factors are $100 = 28.2$ , $\frac{100}{28.2}$ and $\frac{28.2}{100}$ There are three significant and one exact numbers.

1Part(a) Step 1 : Given information

We are given that a bee flies at an average speed of $3.5 m$ per second.

2Part(a) Step 2 : Simplify

According to given information

Equality is $1 s = 3.5 m$

Two conversion factors are $\frac{1 s}{3.5 m}$ and $\frac{3.5 m}{1 s}$

Answer has two significant figure and one exact number.

3Part(b) Step 1 : Given information

We are given that the Daily Value (DV) for potassium is $3.5 g$ .

4Part(b) Step 2 : Simplify

According to given information

equality is $1 D V = 3.5 g$

two conversion factors are $\frac{1 D V}{3.5 g}$ and $\frac{3.5 g}{1 D V}$

There are two significant figure and one exact number.

5Part(c) Step 1 : Given information

We are given that an automobile traveled $2.6 k m$ on $1 L$ of gasoline.

6Part(c) Step 2 : Simplify

According to given information

Equality is $1 L = 2.6 k m$

Two conversion factors are $\frac{1 L}{2.6 k m}$ and $\frac{2.6 k m}{1 L}$

There are two significant figure and one exact number.

7Part(d) Step 1 : Given information

We are given that Silicon makes up $28.2 %$ by mass of Earth's crust.

8Part(d) Step 2 : Simplify

According to given information

equality is $28.2 s i l i c o n = 100 E a r t h' s c r u s t$ by mass

two conversion factors are $\frac{28.2}{100}$ and $\frac{100}{28.2}$

There are three significant figures and one exact numbers.

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