Q. 24 - Precalculus Enhanced with Graphing Utilities

Question

the point (x, y) is on the terminal side of angle  in standard position. Find the exact value of the given trigonometric function

$(6,-3) , \tan \vartheta$

Step-by-Step Solution

Answer

$\tan \vartheta = \frac{-1}{2}$

Step 1. Given information

$(6,-3) , \tan \vartheta$

Step 2. Solving for tan ϑ

We know that for any given point (x,y) 

$\tan \vartheta = \frac{y}{x}$

Using this :

$$\begin{gathered} \tan \vartheta = \frac{y}{x} \\ \tan \vartheta = \frac{-3}{6} \\ \tan \vartheta =\frac{-1}{2} \end{gathered}$$