Q. 237 - Intermediate Algebra

Question

In the following exercises, multiply.

${(6-3\sqrt{2})}^2$

Step-by-Step Solution

Answer

The multiplication of ${(6-3\sqrt{2})}^2$ is $54-36\sqrt{2}$

Step 1. Given

An expression ${(6-3\sqrt{2})}^2$

To multiply the numbers.

Step 2. Multiply the expression

By using the formula,

${(a-b)}^2=a^2+2ab+b^2$

So, ${(6-3\sqrt{2})}^2=(6{)}^2-2(6\left)\right(3\sqrt{2})+{\left(3\sqrt{2}\right)}^2$

                        $=36-36\sqrt{2}+9\left(2\right)$

                       $=36-36\sqrt{2}+18$

                       $=54-36\sqrt{2}$