Q. 2.24 - Elementary Algebra

Question

Translate into an algebraic equation and solve: 

The admission price for the movies during the day is \(7.75. This is \)3.25 less the price at night. How much does the movie cost at night? 

Step-by-Step Solution

Answer

$\text{The movie cost at night is }\$\text{11.00}$

Step 1. Given information

Given :The admission price for the movies during the day is $7.75.

 This is $3.25 less the price at night. 

We have to Translate into an algebraic equation and solve: 

To find  How much does the movie cost at night? 

Step 2. Explanation

$\begin{array}{l}\text{According to given statment :The admission price for the movies during the day is \$7.75.}\\ \text{This is \$3.25 less the price at night.}\\ \text{First we look for what to find.}\\ \text{Let the movie cost at night is M}\\ \text{Now according to given statment}\\ \Rightarrow \text{M-3.25=7.75}\\ \Rightarrow \text{M-3.25+3.25=7.75+3.25 (Add 1025 to both sides)}\\ \Rightarrow \text{M=11.00 (Simplify)}\\ \text{The movie cost at night is }\$\text{11.00}\end{array}$