Q. 2.15 - Elementary Algebra

Question

$\text{Solve: }4\left(2h-3\right)-7h=6\left(h-2\right)-6\left(h-1\right).$

Step-by-Step Solution

Answer

The solution for the given equation is$h=6$.

Step 1. Given information

The given equaiton is $4\left(2h-3\right)-7h=6\left(h-2\right)-6\left(h-1\right).$

We have to solve the given equation.

Step 2. Explanation

$\begin{array}{l}\text{Simplify}\\ \Rightarrow 4\left(2h-3\right)-7h=6\left(h-2\right)-6\left(h-1\right).\\ \Rightarrow 8h-12-7h=6h-12-\text{6h+6}\\ \text{Rearrange the terms}\\ \Rightarrow 8h-7h-12=6h-\text{6h}-12\text{+6}\\ \text{Simplifed as much as possible}\\ \Rightarrow h-12=-12\text{+6}\\ \Rightarrow h-12=-6\\ \text{Add 12 both the side}\\ \Rightarrow h-12+12=-6+12\\ \Rightarrow h=6\end{array}$