Q. 20 - Precalculus Enhanced with Graphing Utilities

Question

In Problems 15–26, determine which functions are polynomial functions. For those that are, state the degree. For those that are not, tell

why not.

$f\left(x\right)=x(x-1)$

Step-by-Step Solution

Answer

$f$ is a polynomial function of degree $2$

Step 1: Given information

$f\left(x\right)=x(x-1)$

Step 2: Calculation

$$\begin{gathered} f\left(x\right)=x(x-1) \\ =x^2-x \end{gathered}$$

$f$ is a polynomial function of degree 2