Q. 20

Question

Find two convergent geometric series k=0ak=L and k=0bk=M with all positive terms such that k=0akbk diverges.

Step-by-Step Solution

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Answer

Ans: 

part (a). The convergent geometric series k=0ak=k=012k

part (b). The convergent geometric series k=0ak=k=014k

part (c). The series  is diverges  k=0akbk=k=02k

1Step 1. Given information:

Consider the two convergent geometric series k=0ak=L and k=0bk=M with all positive terms that k=0akbkdiverges.

2Step 2. Finding the convergent geometric series ∑ k = 0 ∞ a k

Consider the geometric series k=0ak=k=012k.

The series k=012k is a geometric series with common ratio r=12  which is less than 1 . The geometric series with ratio less than 1 is convergent.

Therefore, k=0ak=k=012k is convergent.

3Step 3. Finding the convergent geometric series ∑ k = 0 ∞ b k
Consider the geometric series k=0bk=k=014k.
The series k=014k is a geometric series with common ratio r=14, which is less than 1 .
The geometric series with ratio less than 1 is convergent.
Therefore, k=0ak=k=014k is convergent.
4Step 4. Finding the converges geometric series of ∑ k = 0 ∞ a k b k with all positive terms:

k=02kThe series k=0akbk is

k=0akbk=k=04k2k=k=02k

The series isk=02k a geometric series with common ratio r=2, which is less than 1 . The geometric series with ratio greater than 1 is diverges.

Therefore,  k=0akbk=k=02k is diverges.