Q. 2

Question

2. Let P=(x, y) be a point on the graph of y=x2-8.

(a) Express the distance d from P to the point (0,-1) as a function of x.

(b) What is d if x=0 ?

(c) What is d if x=-1 ?

(d) Use a graphing utility to graph d=d(x).

(e) For what values of xis d smallest?

Step-by-Step Solution

Verified
Answer

The distance is d=x4-13x2+49 and the values are 7,6.08 and the graph is 


 and d is least when x=-2.55,x=2.55

1Part (a) Step 1: Given information

Given the point P(x,y) and the curve y=x2-8

2Part (a) Step 2: Calculate the distance using the distance formula

The distance of P from (0,-1) is d=x2+(y-1)2. So the required distance is

d(x)=x2+x2-8+12d(x)=x2+x2-72d(x)=x2+x4-14x2+49d(x)=x4-13x2+49

3Part (b) Step 1: Given information

Given the equation d(x)=x4-13x2+49

4Part (b) Step 2: Substituting x = 0 and calculating the value

Substituting, we get

d(x)=x4-13x2+49d(0)=04-13(0)2+49d(0)=49d(0)=7

5Part (c) Step 1: Given information

Given the equation d(x)=x4-13x2+49

6Part (c) Step 2: Substituting x = 1 and calculating the value

Substituting, we get

d(x)=x4-13x2+49d(1)=14-13(1)2+49d(1)=37

7Part (d) Step 1: Given information

Given the equation d(x)=x4-13x2+49

8Part (d) Step 2: Sketching the graph

The graph is 



9Part (e) Step 1: Given information

Given the equation d(x)=x4-13x2+49

10Part (e): Checking the graph

The value of d is least when x=-2.55,x=2.55