Q. 19
Question
Make a copy of the graph of f used in Exercises 11 and 13, and sketch additional secant lines to illustrate that as (or equivalently, as ) the slopes of the secant line get closer and closer to the slope of the tangent line to f at .
Step-by-Step Solution
Verified Answer
From the graph with many secant lines, we can observe that, as for the secant lines, the slope of the secant lines is getting closer and closer to the tangent of the function.
1Step 1. Given Information.
The graph of the function.
2Step 2. Draw some secant lines.
Draw some secant lines on the function.
3Step 3. Observe the graph.
From the graph, we can conclude that as for the secant lines, the slope of the secant lines is getting closer and closer to the tangent of the function.
Other exercises in this chapter
Q. 17
Consider again the function f graphed at the left. At which values of x does f have the greatest instantaneous rate of change? The least? At which values of x&n
View solution Q. 18
Consider again the function g(x) graphed at the right. For which values of x does g(x) have a positive instantaneous rate of change? Negative? Zero?
View solution Q. 20
The derivative of a smooth function f at a point x=c can also be approximated with a symmetric difference quotient:f'(c)≈f(c+h)-f(c-h)2h(a) Use
View solution Q. 22
In Exercises 21–24, sketch the graph of a function f that has the listed characteristics. f'(-3)=0;f'(-1)=0; f'(2)=0
View solution