Q 1.87.

Question

In a designed experiment, there are two factors, say, Factor and Factor B. Factor has three levels, say, a1, a2 and a3; Factor has four levels, say, b1, b2, b3 and b4.

(a)  Construct a schematic for the treatments similar to Table 1.8 on page 27. 

(b)  Use part ( a ) to determine the number of treatments. 

(c)  Could you have determined the answer for part ( b ) without constructing the schematic in part ( a )? Explain your answer.

Step-by-Step Solution

Verified
Answer

Part (a)

Part (b) 12

Part (c) 12

1Part (a) Step 1. Given information.

The given statement is:

In a designed experiment, there are two factors, say, Factor and Factor B. Factor has three levels, say, a1, a2 and a3; Factor has four levels, say, b1, b2, b3 and b4.

2Part (a) Step 2. Construct a schematic for the treatments similar to Table 1.8 on page 27.

Construct a schematic for the treatments as shown below:

3Part (b) Step 1. Determine the number of treatments.

There are twelve combinations based on the schematic for the treatments obtained in part (a).


As a result, there are a total of twelve treatments.

4Part (c) Step 1. Determine the number of treatments without constructing the schematic.

The number of levels for factor is three, while factor has four levels.


The number of treatments will equal the product of factor and factor :

=Number of levels of factor A × Number of levels of factor B=3×4=12

As a result, The total number of levels is 12.