Q 178.

Question

Solve the system of equations:

x+2z=04y+3z=-22x-5y=3

Step-by-Step Solution

Verified
Answer

The solution for the system of equations is,

x=4y=1z=-2.

1Step 1. Given the information

The system of equations is,

x+2z=0.............(1)4y+3z=-2........(2)2x-5y=3...........(3)

2Step 2. Eliminating z from the equations (1) and (2).

Eliminating z with the equations (1) and (2)

-3x-6z=0.......(1)×-38y+6z=-4......(2)×2

Solving the equations we get,

-3x+8y=4.....(4)

3Step 3. Solving the equations (3) and (4) to find the value of y .

Solving the equations (3) and (4),

-6x+16y=-8........(4)×2   6x-15y=9..........(3)×3

Adding the equations we get,

16y-15y=-8+9y=1

4Step 4. Finding the value of x .

Substituting y=1 in the equation

2x-5y=3,

2x-5(1)=32x-5=32x=3+52x=8x=4

5Step 5. Finding the value of z .

Substituting x=4in the equation

x+2z=0,

4+2z=02z=-4z=-2

6Step 6. Checking the solution for the equation x + 2 z = 0 .

Substituting x=4y=1z=-2 in the equation

x+2z=0,

4+2(-2)=04-4=00=0

This is true.

7Step 7. Checking the solution for the equation 4 y + 3 z = - 2 .

Substituting x=4y=1z=-2 in the equation

4y+3z=-2,

4(1)+3(-2)=-24-6=-2-2=-2

This is true.

8Step 8. Checking the solution for the equation 2 x - 5 y = 3 .

Substituting x=4y=1z=-2 in the equation

2x-5y=3

2(4)-5(1)=38-5=33=3

This is true.