Q 171. - Intermediate Algebra

Question

In the following exercises, factor completely using the perfect square trinomials pattern.

$10j{k}^2+80jk+160j$

Step-by-Step Solution

Answer

The factor of the trinomial is $10j{\left(k+4\right)}^2$.

Step 1. Given information.

Consider the given trinomial.

$10j{k}^2+80jk+160j$

Step 2. Factor out GCF.

Factor out $10j$ from the given trinomial.

$10j\left(k^2+8k+16\right)$

Step 3. Find the factor of perfect square trinomial.

The middle term of the trinomial is positive so the binomial square will be of the form  ${\left(a+b\right)}^2$.

$10j\left[{\left(k\right)}^2+2·k·4+{\left(4\right)}^2\right]$

Write factor

$10j{\left(k+4\right)}^2$