Q. 17 PPS - Algebra 1

Question

 Evaluate the following expression and name the property used in each step:

$\mathbf{25}\mathbf{+}\mathbf{14}\mathbf{+}\mathbf{15}\mathbf{+}\mathbf{36}$

Step-by-Step Solution

Answer

The value of the expression is: $\mathbf{25}\mathbf{+}\mathbf{14}\mathbf{+}\mathbf{15}\mathbf{+}\mathbf{36}\mathbf{=}\mathbf{90}$.

Step 1 – Given information.

The given expression is:
$25+14+15+36$

Step 2 – Write the concept.

The substitution property for multiplication, addition and subtraction is: 

$\begin{array}{c}a\cdot b=c\\ a÷b=c\\ a\pm b=c\end{array}$

The commutative property is:

$a+b=b+a$

Step 3 – Evaluate the expression.

The expression $25+14+15+36$ can be solved in below:

$\begin{array}{c}25+14+15+36=\left(25+15\right)+\left(14+36\right)\text{\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}}\left(\text{Commutative\hspace{0.17em}\hspace{0.17em}Property}\right)\\ =\left(40\right)+\left(50\right)\text{\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}}\left(\text{Substitution\hspace{0.17em}\hspace{0.17em}Property}\right)\\ =90\text{\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}}\left(\text{Substitution\hspace{0.17em}\hspace{0.17em}Property}\right)\end{array}$