Q. 15.90 - An Introduction to General, Organic, and Biological Chemistry

Question

One of the triacylglycerols in olive oil is glyceryl tripalmitoleate (tripalmitolein). 

a. Draw the condensed structural formula for glyceryl tripalmitoleate (tripalmitolein).

b. How many liters of ${\mathrm{H}}_2$ gas at STP are needed to completely saturate $100 g$ of glyceryl tripalmitoleate (tripalmitolein)?

c. How many milliliters of a $0.250 M NaOH$ solution are needed to completely react with $100 g$ of glyceryl tripalmitoleate (tripalmitolein)?

Step-by-Step Solution

Answer

(Part a)

(Part b) To totally permeate $100 g$ of gelucire tripalmitoleate (tripalmitolein) at STP is $8.38 L$.

(Part c) the proportion of $NaOH$ favorable result to saponify $100mg$ of glyceryl tripalmitoleate (tripalmitolein) is $1.50\times {10}^3\mathrm{mLNaOH}\text{ solution }$.

(Part a) Step 1: Introduction.

Glyceryl tripalmitoleate (tripalmitolein) is a triacylglycerol constituted of glycerol and three palmitoleic acid atoms united by linkers.

(Part a) Step 2: Given Information.

Glycerol's three hydroxyl groups start ester interactions with three palmitoleic acid molecules' carboxyl groups. 

(Part a) Step 3: Explanation.

To design overall structure of glyceryl tripalmitoleate, we still must sketch the compositions of glycerol and palmitoleic acid. 

                                   

The structure of palmitoleic acid,

                         

The structural formula for glyceryl tripalmitoleate

                     

(Part b) Step 4: Given Information.

Three palmitoleic acids are connected to the triglycerides in glyceryl tripalmitoleate (tripalmitolein). In the backbone of stearic acid, there is still a greenhouse gas dual.

(Part b) Step 5: Explanation.

A fatty acid is synthesized while water is added to the all the doubled bonds. Three atoms of water vapor are need to properly permeate every mole of tripalmitolein.

This equivalency might well be phrased with

$1\text{ mol tripalmitolein }=3{\mathrm{molH}}_2$

$1\text{ mol tripalmitolein }=801.25\mathrm{g}\text{ tripalmitolein }$

$\text{ 100. gtripalmitelein }\times \frac{1\text{ meltripalmitelein }}{801.25\text{ g tripalmitelein }}\times \frac{3\mathrm{molH}}{1\text{ mel tripalmitelein }}=0.374{\mathrm{molH}}_2$

From the particles of biogas, we may measure the capacity of $H_2$ propane in litres. A molecule of any vapor maintains a radius of $22.4L$ at STP temperature. As an outcome, we've

$1\mathrm{mol}\text{ of }{\mathrm{H}}_2=22.4\mathrm{L}\text{ of }{\mathrm{H}}_2$

$0.374{\mathrm{melH}}_2\times \frac{22.4{\mathrm{LH}}_2}{1\mathrm{melH}}=8.38{\mathrm{LH}}_2$

As a measure, the proportion of $H_2$ gas expected to totally permeate $100 g$ of gelucire tripalmitoleate (tripalmitolein) at STP is $8.38 L$.

(Part c) Step 6: Given Information.

An ester reactions with a good platform, such like $NaOH$, to generate the stock solution of carboxyl group in a saponification reaction. 

(Part c) Step 7: Explanation.

A triacylglycerol is glyceryl tripalmitoleate (tripalmitolein). To entirely saponify one mole of tripalmitolein, three moles of $NaOH$ are sufficient. This equivalency may indeed be expressed thus

$\text{ Triacylglycerol }+3\mathrm{NaOH}\to 3\text{ sodium salts of fatty acid }+\text{ glycerol }$

Tripalmitolein already has a molar mass of $801.25\mathrm{g}/\mathrm{mol}$. As a result, we get the corresponding inclusivity:

$1\text{ mol tripalmitolein }=801.25\mathrm{g}\text{ tripalmitolein }$

$\begin{array}{r}\text{ 100. gtripalmitelein }\times \frac{1\text{ mel tripalmiteleint }}{801.25\mathrm{g}\text{ tripalmitelein }}\times \frac{3\mathrm{molNaOH}}{1\text{ mel tripalmitelein }}\\ \end{array}$

$=0.374\mathrm{molNaOH}$

$0.250\mathrm{MNaOH}\text{ solution }=\frac{0.250\mathrm{molNaOH}}{1\mathrm{LNaOH}\text{ solution }}$

$1000\mathrm{mL}=1\mathrm{L}$

$\text{ Volume of }\mathrm{NaOH}\text{ solution }=0.374\mathrm{melNaOH}\times \frac{1\pm \mathrm{NaOH}\text{ solution }}{0.250\mathrm{melNaOH}}\times \frac{1000\mathrm{mL}}{1\mathrm{L}}$

$=1.50\times {10}^3\mathrm{mLNaOH}\text{ solution }$

As a result, the proportion of $NaOH$ favorable result to saponify $100 mg$ of glyceryl tripalmitoleate (tripalmitolein) is $1.50\times {10}^3\mathrm{mLNaOH}\text{ solution }$
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