Q 1.4E - University Physics with Modern Physics

Question

Question:The density of gold is 19.3 g/cm3 . What is this value in kilograms per cubic meter?

Step-by-Step Solution

Answer

Answer

 

The density of gold in kg/m³ is 19300 kg/m³.

 

Step 1: Density and its unit

Density is the ratio of the mass of the body to its volume. Hence, if we take mass as kg and volume as m³, then the SI  unit of density becomes kg/m³.

 

Given data:

The density of gold is ρ=19.3 g/cm³.

Step 2: Determination of density in SI unit

The density in kg/m³ can be calculated as,

 $\begin{array}{l}\rho =19.3{\text{\hspace{0.17em}g/cm}}^{\text{3}}\times \frac{\text{1\hspace{0.17em}kg}}{\text{1000\hspace{0.17em}g}}\times {\left(\frac{\text{100\hspace{0.17em}cm}}{\text{1\hspace{0.17em}m}}\right)}^3\\ \rho =19300{\text{\hspace{0.17em}kg/m}}^3\end{array}$

 

Hence from the above calculation we can say 19300 kg/m³ is the value of density in kilograms per cubic meter.