Q. 14.80 - An Introduction to General, Organic, and Biological Chemistry

Question

Ethyl octanoate is a flavor component of mangoes. 

1. Draw the condensed structural formula for ethyl octanoate.
2. Write the balanced chemical equation for the formation of ethyl octanoate.
3. Write the balanced chemical equation for the acid hydrolysis of ethyl octanoate.
4. Write the balanced chemical equation for the base hydrolysis of ethyl octanoate with $NaOH$.
5. How many milliliters of a $0.315 \mathrm{M} \mathrm{NaOH}$ solution is needed to completely hydrolyze (saponify) $2.84 \mathrm{g}$ of ethyl octanoate?

Step-by-Step Solution

Answer

Part (a) : Structure of ethyl octanoate is below-  

Part (b) Balanced Chemical Equation for the formation of Ethyl octanote is below-

Part (c) The balanced chemical equation for the acid hydrolysis of Ethyl octanoate is below-

Part (d) The balanced chemical equation for the base hydrolysis of ethyl octanoate with $NaOH$ is below-

Part (e) 52.4 ml of a  solution is required to completely hydrolyze $2.84 g$ of ethyl octanoate.

Part (a)

Part (b) 

Part (c) 

Part (d) 

Part A Step 1: Given Information We need to find the Structure of Ethyl octanote Component

• Mango flavor component  is ethyl octanote. 
• Structure of ethyl octanoate is 

Part B Step 2: Given Information We need to find Balanced Chemical Equation for the formation of Ethyl octanote

• Ethyl octanoate can be made by reacting ethanol with octanoate.
• Balanced Chemical Equation for the formation of Ethyl octanote is

Part C Step 3: Given Information We need to find the balanced chemical equation for the acid hydrolysis of Ethyl octanoate

• Acid hydrolysis of ethyl octanoate yields ethanol and octanoate. 
• The balanced chemical equation for the acid hydrolysis of Ethyl octanoate is 

Part D Step 4: Given Information

•  The products of basic hydrolysis of ethyl octanoate with $NaOH$ are ethanol and carboxylates.
• The balanced chemical equation for the base hydrolysis of ethyl octanoate with $NaOH$is

Part E Step 5: Given information

Given $2.840 \mathrm{g}$ ethyl octanoate $\left({\mathrm{C}}_{10}{\mathrm{H}}_{20}{\mathrm{O}}_2\right)$ and $0.315 \mathrm{M} \mathrm{NaOH}$

Need $\mathrm{ml}$ of $0.315 \mathrm{M} \mathrm{NaOH}$

Part E Step 6: Explanation

${\mathrm{gC}}_{10}{\mathrm{H}}_{20}{\mathrm{O}}_2$ molar moles ${\mathrm{C}}_{10}{\mathrm{H}}_{20}{\mathrm{O}}_2$ Mole-mole moles $\mathrm{NaOH}$

mass factor

Molrity L $NaOH$ Metric ML

System $\mathrm{NaoH}$

Part E Step 7: Explanation

Using Equalities/ Conversion factors 

Step 8: Explanation (Part E) The Volume of N a O H solution required to hydrolyze ethyl octanote

$2.840 {\mathrm{gC}}_{10}{\mathrm{H}}_{20}{\mathrm{O}}_2\times \frac{1{\text{ mole }}_{10}{\mathrm{H}}_{20}{\mathrm{O}}_2}{1{\text{ mole }}_{10}{\mathrm{H}}_{20}{\mathrm{O}}_2}\times \frac{1\text{ mole NaOH }}{1\text{ mole }{\mathrm{C}}_{10}{\mathrm{H}}_{20}{\mathrm{O}}_2}\times \frac{1 \mathrm{L} \mathrm{NaOH}}{0.315 \mathrm{mole} \mathrm{NaOH}}\times \frac{1000 \mathrm{ml} \mathrm{NaOH}}{1 \mathrm{L} \mathrm{NaOH}}$

= 52.4 ml of 0.315 M $NaOH$