Q. 14.46

Draw the condensed structural or line-angle formulas for the products from the hydrolysis of each of the following amides with $NaOH$ :

Verified

Answer

( part a) 2-methylbutanamide produces sodium 2-methylbutanoate and sodium 2- methylbutanoate.

(part b) N, N-diethylbutanamide hydrolysis produce sodium butanoate and diethylamine.

(part c) N.butyibenzamide is to produces sodium benzoate and butylamine.

(part d) Base hydrolysis creates sodium 2-cholopropanoate and ethylamine from the molecule

2- chloro-N-ethyl-N-methylpropanamide.

(part e) N-propylbenzamide is hydrolyzed by a base, yielding sodium benzoate and propylamine.

1Step -1 Introduction (part a)

Amides are carboxylic acid derivatives in which the hydroxyl group has been replaced with an amine.
Amidation is a process in which carboxylic acid combines with a substrate to produce amide.
A water molecule is removed in this reaction, and the carboxylic acid and amine molecules unite to produce the amide.

Amides are divided by a hydrolysis reaction in which a water molecule is added to the amide.
When $NaOH$ is introduced, carboxylate salts, ammonia, or an amine are the hydrolysis products.

2Step - 2 Given information (part-a)

A base hydrolyzes 2-methylbutanamide to produce sodium 2-methylbutanoate and sodium 2-methylbutanoate.

3Step - 3 Explanation (part-a)

4Step - 4 Given information (part-b)

N, N-diethylbutanamide hydrolysis generates sodium butanoate and diethylamine.

5Step - 5 Explanation (part-b)

6Step - 6 given information (part- c)

N.butyibenzamide is hydrolyzed by a base to create sodium benzoate and butylamine.

7Step - 7 Explanation (part-c)

8Step - 8 Given information (part-d)

Base hydrolysis produces sodium 2-cholopropanoate and ethylamine from the molecule 2-chjoro-N-ethyl-N-methylpropanamide.

9Step - 9 Explanation (part-d)