Q. 1.44 - An Introduction to General, Organic, and Biological Chemistry

Question

Evaluate each of the following: $\left(1.4\right)$

a. $-95-\left(-11\right)=\_\_\_$.

b. $\frac{152}{-19}=\_\_\_$.

c. $4-56=\_\_\_$.

Step-by-Step Solution

Answer

a. The answer is $-95-\left(-11\right)=-84$.

b. The answer is  $\frac{152}{-19}=-8$.

c. The answer is  $4-56=-52$.

Part (a) step 1: Given Information

We need to evaluate $-95-\left(-11\right)=\_\_\_$.

Part (a) step 2: Calculation

Now,

subtraction of two negative numbers.

$$\begin{gathered} =-95-\left(-11\right) \\ =-95+11 \\ =-84 \end{gathered}$$

Part (b) step 1: Given Information

We need to evaluate $\frac{152}{-19}=\_\_\_$.

Part (b) step 2: Calculation

Here,  $152$ divided by $-19$.

when one positive number is divided by any negative number so the result comes in a negative sign.

$$\begin{gathered} =\frac{152}{-19} \\ =-8 \end{gathered}$$

Part (c) step 1: Given Information

We need to evaluate $4-56=\_\_\_$.

Part (c) step 2: Calculation

Here,

$$\begin{gathered} =4-56 \\ =4+\left(-56\right) \\ =-52 \end{gathered}$$