Q. 13 - Precalculus Enhanced with Graphing Utilities

Question

In Problems 7–18, match each graph to one of the following functions:

$$\begin{gathered} \mathit{A}\mathbf{.} y = x^2+ 2 \mathit{B}\mathbf{.} y = -x^2 + 2 \mathit{C}. y = \left|x\right| + 2 \\ \mathit{D}\mathbf{.} y = -\left|x\right|+ 2 \mathit{E}\mathbf{.} y = {(x - 2)}^2 \mathit{F}\mathbf{.} y = -{(x + 2)}^2 \\ \mathit{G}\mathbf{.} y = \left|x-2\right| \mathit{H}\mathbf{.} y = -\left|x+2\right| \mathit{I}\mathbf{.} y = 2x^2 \\ \mathit{J}\mathbf{.} y = -2x^2 \mathit{K}\mathbf{.} y = 2\left|x\right| \mathit{L}\mathbf{.} y = -2\left|x\right| \end{gathered}$$

Step-by-Step Solution

Answer

The given graph is matched to the function $\mathit{L}\mathbf{.}\mathbf{ }y=-2\left|x\right|.$

Step 1. Given Information

There is the given graph we have to match each graph to its functions.

Step 2. Identifying the function of the graph

When the right side of the function $y=f\left(x\right)$ is multiplied by $-1$ the graph of the new function $y=-f\left(x\right)$ is the reflection about the x-axis of the graph of the function $y=f\left(x\right)$.

Thus, the function whose graph is the reflection of the graph of $y=\left|x\right|$ in the x-axis is $y=-\left|x\right|.$

The given graph is a reflection in the x-axis of the graph of the function $y=\left|x\right|$ but it is vertically stretched by a factor of $2.$

Step 3. Stating the function of the graph

When the right side of a function $y=f\left(x\right)$ is multiplied by a positive number a, the graph of the new function $y=af\left(x\right)$ is obtained by multiplying each y-coordinate on the graph of $y=f\left(x\right)$ by a. The new graph is a vertically stretched $(if a>1)$ version of the graph of $y=f\left(x\right).$

Since the graph is vertically stretched by factor of $2.$

The function of the given graph is $y=-2\left|x\right|$ that matched to option L.