Q. 12.49 - An Introduction to General, Organic, and Biological Chemistry

Question

Which compound in each pair would be more soluble in water? Explain. ($12.2$)

a. $bu\tan e$ or $1-propanol$

b. $2-propanol$ or $diethyl ether$

c. $ethanol$ or $1-hexanol$

Step-by-Step Solution

Answer

(a) The $1-propanol$ will be more soluble in water

(b) The $2-propanol$ will be more soluble in water

(c) The $ethanol$ will be more soluble in water

Part (a) Step 1: Given information

We need to find that which out of the $bu\tan e$ and $1-propanol$ will be more soluble in water

Part (a) Step 2: Explanation

We know that

The compound which will form more hydrogen bonds will be more soluble in water.

And out of the given compounds $1-propanol$ will form hydrogen bonds

Therefore, The $1-propanol$ will be more soluble in water 

Part (b) Step 1: Given information

We need to find that which out of the $2-propanol$ and $diethyl ether$ will be more soluble in water 

Part (b) Step 2: Explanation

We know that

The compound which will form more hydrogen bonds will be more soluble in water.

And out of the given compounds $2-propanol$ will form hydrogen bonds

Therefore, The $2-propanol$ will be more soluble in water 

Part (c) Step 1: Given information

We need to find that which out of the $ethanol$ and $1-hexanol$ will be more soluble in water 

Part (c) Step 2: Explanation

We know that

The compound which will form more hydrogen bonds will be more soluble in water.

And out of the given compounds $ethanol$ will form hydrogen bonds

Therefore, The $ethanol$ will be more soluble in water