Q 117

Question

Use the periodic and even–odd properties. 

Iff(θ)=secθ and f(a)=-4, find the exact value of :

(a) f(-a)

(b) f(a)+f(a+2π)+f(a+4π).

Step-by-Step Solution

Verified
Answer

(a) The value of f(-a) is -4.

(b) The value of f(a)+f(a+2π)+f(a+4π) is -12.

1Step 1. Given Information

We have given that following function :-  

f(θ)=secθ and f(a)=-4.

We have to find the value of f(-a) and value of f(a)+f(a+π)+f(a+4π).

To find value of f(-a) we will use even-odd properties and to find the value of f(a)+f(a+2π)+f(a+4π) we will use periodic properties.

2Step 2. Part (a). To find value of f ( - a )

We have given that :-

f(θ)=secθ and f(a)=-4.

We know that :-

sec(-θ)=secθ.

Now put θ=-a, in f(θ)=secθ, then we have :-

f(-a)=sec(-a)f(-a)=sec(a)f(-a)=f(a)

Put f(a)=-4, then we have :-

f(-a)=-4.

This is the required value.

3Step 3. Part (b). To find value of f ( a ) + f ( a + 2 π ) + f ( a + 4 π )

We have given that :-

f(θ)=secθ.

We know that secant function is of period 2π.

This gives us :-

sec(θ+2πk)=secθ, for any integer k.

Now :-

f(a)+f(a+2π)+f(a+4π)=sec(a)+sec(a+2π)+sec(a+4π)f(a)+f(a+2π)+f(a+4π)=sec(a)+sec(a)+sec(a)f(a)+f(a+2π)+f(a+4π)=3sec(a)f(a)+f(a+2π)+f(a+4π)=3f(a)

Put f(a)=-4, then we have :-

f(a)+f(a+2π)+f(a+4π)=3(-4)f(a)+f(a+2π)+f(a+4π)=-12

This is the required value.