Q. 11.50

Question

Give the IUPAC name (including cis or trans, if needed) for each of the following:


Step-by-Step Solution

Verified
Answer

Part(a) IUPAC name is 2-Methylpentene

Part(b) IUPAC name is 3-Methylcyclohexene

Part(c) IUPAC name is Cis-Hex-2-ene

1Part(a) Step 1 : Given information

We need to find IUPAC name of compound .


2Part(a) Step 2 : Simplify

We are given a compound having five carbons with one double bond and one methyl group at second carbon as substituent. So according to IUPAC rules , the name of compound should end with "ene" due to double bond and starts with suffix "Pent" due to five carbons.

Hence,

IUPAC name is 2-Methyl pentene

3Part(b) Step 1 : Given information

We need to find IUPAC name of compound


4Part(b) Step 2 : Simplify

We are given a compound having six carbons with one double bond in cyclic structure and one methyl group at third carbon as substituent. So according to IUPAC rules , the name of compound should end with "ene" due to double bond and starts with suffix "hex" due to six carbons with "cyclo" due to cyclic structure.

Hence,

IUPAC name is 3-Methylcyclohexene

5Part(c) Step 1 : Given information

We need to find IUPAC name of compound 


6Part(c) Step 2 : Simplify

We are given a compound having six carbons with one double bond in cis form. So according to IUPAC rules , the name of compound should end with "ene" due to double bond and starts with suffix "Hex" due to six carbons with "cis" .

Hence,

IUPAC name is Cis-Hex-2-ene