Q. 11.41

Question

Match the following physical and chemical properties with pottasium chloride, KCL, used in salt substances, or butane used in lighters.

a) melts at -138°C

b) burn vigorously in air

c) melts at 770°C

d) contains iconic bonds

e) is a gas at room temperature.

Step-by-Step Solution

Verified
Answer

a) The answer for this part is Butane

b) The answer for this part is  Butane

c) The answer for this part is  KCL

d) The answer for this part is  KCL

e) The answer for this part is Butane

1Part (a) Step1 : Given information

We have to match the physical and chemical properties according to the given compounds  pottasium chloride, KCL, used in salt substances, or butane used in lighters. 

2Part (a) Step 2: Explanation

It is at the room temperature. So , it is an organic compound.

The answer for this part is:

Butane

3Part (b) Step1 : Given information

We have to match the physical and chemical properties according to the given compounds  pottasium chloride, KCL, used in salt substances, or butane used in lighters. 

4Part (b) Step 2: Explanation

It is at the room temperature. So , it is an organic compound.

The answer for this part is:

Butane

5Part (c) Step1 : Given information

We have to match the physical and chemical properties according to the given compounds  pottasium chloride, KCL, used in salt substances, or butane used in lighters. 

6Part (c) Step 2: Explanation

It melts at high temperature. So, it is an inorganic compound.

The answer for this part is:

KCL

7Part (d) Step1 : Given information

We have to match the physical and chemical properties according to the given compounds  pottasium chloride, KCL, used in salt substances, or butane used in lighters. 

8Part (d) Step 2: Explanation

It melts at high temperature. So, it is an inorganic compound.

The answer for this part is:

KCL

9Part (e) Step1 : Given information

We have to match the physical and chemical properties according to the given compounds  pottasium chloride, KCL, used in salt substances, or butane used in lighters. 

10Part (e) Step 2: Explanation

It is at the room tempreature. So , it is an organic compound.

The answer for this part is:

Butane