Q 10. - Calculus

Question

Write each of the inequalities in interval notation:

$\left|\left(3x+1\right)-2\right|<0.1$

Step-by-Step Solution

Answer

Solution is $\left(0.3,0.3666...\right)$

Step 1. Given information

An inequality is $\left|\left(3x+1\right)-2\right|<0.1$

Step 2. Solution of the inequality.

$\begin{array}{rcl}\left|\left(3x+1\right)-2\right|& <& 0.1\\ -0.1& <& \left(3x+1\right)-2<0.1\end{array}$

$x>0.3$ and $x<0.3666...$

So, solution is $\left(0.3,0.3666...\right)$