Q. 1 - Precalculus Enhanced with Graphing Utilities

Question

The intercepts of the equation $9x^2+4y=36$ are ____________.

Step-by-Step Solution

Answer

The solution is $\left(-2,0\right),\left(2,0\right),\left(0,9\right)$ .

Step 1. Given information

Equation: $9x^2+4y=36$

Step 2. Calculation

Let $y=0$ 

$9x^2+4\left(0\right)=36$

        $\frac{9x^2}{9}=\frac{36}{9}$

        $\sqrt{x^2}=\sqrt{4}$

             $x=\pm 2$

The x-intercepts are $-2$ and $2$ . Now let $x=0$

$9\left(0\right)+4y=36$

        $\frac{4y}{4}=\frac{36}{4}$

            $y=9$

The y-intercept is $9$ .

Therefore, the intercepts of the equation $9x^2+4y=36$ are$\left(-2,0\right),\left(2,0\right),\left(0,9\right)$ .