Q. 1

Question

A company claims that each batch of its deluxe mixed nuts contains 52% cashews, 27% almonds, 13% macadamia nuts, and 8% brazil nuts. To test this claim, a quality control inspector takes a random sample of 150 nuts from the latest batch. The one-way table below displays the sample data.

(a) State appropriate hypotheses for performing a test of the company’s claim. 

(b) Calculate the expected counts for each type of nut. Show your work 

Step-by-Step Solution

Verified
Answer

(a)H0:pc=52%,pa=27%,pm=13%,pb=8%; H1 : One of the Pi test is wrong.

(b) The expected count of nuts are : 

 CashewsAlmondsMacadamiaBrazil
7840.519.512
1Part (a) Step 1: Given Information

Given in the question that, the each batch of mixed nuts contains 52% cashews, 27% almonds, 13% macadamia nuts, and 8% brazil nuts.

2Part (a) Step 2: Explanation

H0: will be the null hypothesis. The observed count of each type of nut in a group of 150 nuts from the most recent batch matches the reported count of nuts in a group of 150

H0:pc=52%,pa=27%,pm=13%,pb=8%

H1: The observed counts of each type of nut in a group of  150 nuts from the most recent batch do not match the reported count of nuts in a 150 group.

Because the claim specifies a proportion of each type of nut of 100, we can calculate the proportion of each type of nut in 150 by multiplying each number by 150.

3Part (b) Step 1: Given Information

Given in the question that,


4Part (b) Step 2: Explanation

According to the information, 

Here,

n=150

P( cashews )=52%=0.52

P( almonds )=27%=0.27

P( Macadamia )=13%=0.13

P(brazil)=8%=0.08

The expected count is then calculated as the product of the sample size n and the type probability:

Cashews:

150(0.52)=78

Almonds:

150(0.27)=40.5

Macadamia:

150(0.13)=19.5

Brazil:

150(0.08)=12

Therefore, the expected counts of nuts are

 Cashews  Almonds  Macadamia  Brazil 7840.519.512