Problem 99
Question
The graph of \(f(x)=a \log x\) passes through the point \((10,3) .\) Find \(a\) and thus the complete expression for \(f\) Check your answer by graphing \(f\).
Step-by-Step Solution
Verified Answer
The constant \(a\) is approximately 1.43 and, thus, the complete expression for \(f\) is \(f(x) = 1.43 \log x\). The graph of \(f\) should pass through \((10,3)\) and confirm this result.
1Step 1: Insert the Point Coordinates into the Equation
The given point \((10,3)\) can be written as \((x, f(x))\). The coordinates can then be inserted into the formula \(f(x) = a \log x\), resulting in the equation \(3 = a \log 10\).
2Step 2: Solve the Equation for \(a\)
Isolate \(a\) to find its value by dividing both sides of the equation by \(\log 10\). This results in \(a = 3/\log 10\). When calculating through, you'll find that \(a \approx 1.43\).
3Step 3: Write the Complete Expression for \(f\)
With \(a\) known, one can write down the full expression for \(f\), which will be \(f(x) = 1.43 \log x\).
4Step 4: Graph the Function
Draw the graph of \(f\). The function should pass through the point \((10,3)\) and have a slope approximately equal to 1.43 at that point.
Key Concepts
Graphing FunctionsFinding ParametersMathematical ProofFunction Evaluation
Graphing Functions
Graphing functions can be a helpful way to see how mathematical expressions behave visually. In this case, we're mapping a logarithmic function, which has the general form of \(f(x) = a \log x\). The graph of this function has distinct characteristics:
- It passes through the point \((1,0)\) when \(aeq0\) because \(\log 1 = 0\).
- It's always increasing if \(a > 0\) since the log function increases as \(x\) increases.
Finding Parameters
Finding parameters involves solving for unknowns in a function using given information. In this exercise, the parameter to be found is \(a\) in the expression \(f(x) = a \log x\). We know the function passes through the point \((10,3)\), meaning when \(x = 10\), \(f(x) = 3\).
To find \(a\), substitute these values into the equation:
To find \(a\), substitute these values into the equation:
- \(3 = a \log 10\)
- Solve for \(a\) to get \(a = \frac{3}{\log 10}\)
- \(f(x) = 3 \log x\)
Mathematical Proof
Mathematical proof is about validating the assumptions and ensuring the calculated outcomes are consistent with the known properties. In this problem, we've determined that \(a = \frac{3}{\log 10}\). To ensure this is indeed correct, understand that the logarithm of 10 in base 10 equals 1.
Thus, \(a = \frac{3}{1} = 3\). By checking back to our function \(f(x) = 3 \log x\), when we input \(x = 10\), the output is 3, which aligns with the point \((10,3)\) given in the problem.
Thus, \(a = \frac{3}{1} = 3\). By checking back to our function \(f(x) = 3 \log x\), when we input \(x = 10\), the output is 3, which aligns with the point \((10,3)\) given in the problem.
- Substituting to verify: \(f(10) = 3 \log 10 = 3\)
Function Evaluation
Function evaluation refers to determining the output of a function for a particular input. Based on the provided exercise, evaluate \(f(x)\) at specific values to verify accuracy. Now that we've established \(f(x) = 3 \log x\), let's evaluate some examples:
- When \(x = 1\), \(f(1) = 3 \log 1 = 3 \times 0 = 0\)
- When \(x = 10\), \(f(10) = 3 \log 10 = 3\)
- When \(x = 100\), \(f(100) = 3 \log 100 = 3 \times 2 = 6\)
Other exercises in this chapter
Problem 97
Explain how you could use the following table of values for the function \(f(x)=10^{x}\) to find the given quantity. $$\begin{array}{cc} x & f(x)=10^{x} \\ 0.47
View solution Problem 98
Explain how you could use the following table of values for the function \(f(x)=10^{x}\) to find the given quantity. $$\begin{array}{cc} x & f(x)=10^{x} \\ 0.47
View solution Problem 100
The graph of \(f(x)=A \ln x+B\) passes through the points (1,2) and \((e, 4)\) (a) Find \(A\) and \(B\) using the given points. (b) Check your answer by graphin
View solution Problem 101
Sketch graphs of the two functions to show that \(\log _{1 / 2} x=-\log _{2} x .\) (The equality can be established algebraically by techniques in the following
View solution