Problem 99
Question
Problem: The length of a rectangle is \(3 \mathrm{~cm}\). Its width is \(8 \mathrm{~cm}\). Find its area. $$ \text { Incorrect Answer: } \begin{aligned} A &=L W \\ A &=3 \cdot 8 \\ A &=24 \end{aligned} $$
Step-by-Step Solution
Verified Answer
The area of the rectangle is 24 cm\textsuperscript{2}.
1Step 1: Identify the Formula
The formula for the area of a rectangle is given by the product of its length (L) and width (W).
2Step 2: Substitute the Values
Substitute the given values into the formula. Here, the length (L) is 3 cm, and the width (W) is 8 cm.
3Step 3: Perform the Multiplication
Multiply the length by the width: \[ A = 3 \text{ cm} \times 8 \text{ cm} = 24 \text{ cm}^2 \]
4Step 4: Interpret the Result
The calculated area of the rectangle is 24 square centimeters.
Key Concepts
RectangleArea CalculationBasic Geometry
Rectangle
A rectangle is a four-sided figure with opposite sides that are equal in length. Two opposite sides are called the length, and the other two sides are called the width. Rectangles are a fundamental shape in geometry, and you encounter them frequently in everyday objects like books, screens, and tables. Understanding rectangles is crucial because they form the basis for more complex geometric concepts.
Area Calculation
The area of a rectangle is a measure of how much space the rectangle covers. To calculate the area, you use the formula: \( A = L \times W \), where \(A\) represents the area, \(L\) is the length, and \(W\) is the width. This formula works because a rectangle can be visualized as being filled with smaller squares. For example, if the length is 3 cm and the width is 8 cm, you can fit three rows of eight small squares inside the rectangle, resulting in a total of 24 squares. Therefore, the area is 24 square centimeters.
Basic Geometry
Basic geometry involves understanding shapes, their properties, and how to measure them. For rectangles, it's important to note:
- Rectangles have four right angles (each 90 degrees).
- Opposite sides are not only equal but also parallel.
Other exercises in this chapter
Problem 97
\(\frac{3^{2}-5 \cdot 9}{-6^{2}}\)
View solution Problem 98
\(\frac{6 \cdot 8-8^{2}}{-4^{2}}\)
View solution Problem 99
\(\frac{4\left(5^{2}-6 \cdot 4\right)}{3 \cdot 4-6 \cdot 2}\)
View solution Problem 100
\(\frac{3\left(4^{2}-5 \cdot 2\right)}{4 \cdot 8-2 \cdot 16}\)
View solution