Problem 99
Question
If \(f(x)=\tan x\), then \(f^{n}(0)-{ }^{n} C_{2} f^{n-2}(0)+{ }^{n} C_{4} f^{n-4}(0)-\ldots=\) (A) \(\sin \frac{n \pi}{2}\) (B) \(\cos \frac{n \pi}{2}\) (C) \(\tan \frac{n \pi}{2}\) (D) None of these
Step-by-Step Solution
Verified Answer
(B) \( \cos \frac{n \pi}{2} \)
1Step 1: Understanding the Problem
We are given a function \( f(x) = \tan x \) and need to evaluate the expression \( f^{n}(0) - { }^{n} C_{2} f^{n-2}(0) + { }^{n} C_{4} f^{n-4}(0) - \ldots \). This involves understanding the behavior of \( \tan x \) and its derivatives evaluated at \( x = 0 \).
2Step 2: Evaluate Derivatives of \( \tan x \)
The derivatives of \( \tan x \) evaluated at \( x = 0 \) should be determined as they are part of the expression. Note:\( f'(x) = \sec^2 x \). Hence, \( f'(0) = 1 \), \( f''(x) = 2 \tan x \sec^2 x \), which results in \( f''(0) = 0 \) because \( \tan 0 = 0 \), and similarly for higher derivatives evaluated at \( x = 0 \).
Key Concepts
Trigonometric FunctionsHigher Order DerivativesBinomial Theorem
Trigonometric Functions
Trigonometric functions are fundamental in the study of mathematics, especially calculus. They include sine, cosine, and tangent functions. These functions relate the angles and sides of a right-angled triangle. Among these, the tangent function, denoted as \(\tan x\), is very potent, owing to its properties and applications.
- Definition: The tangent of an angle is defined as the ratio of the opposite side to the adjacent side in a right-angled triangle.
- Periodicity: The function \(\tan x\) has a periodicity of \(\pi\), meaning it repeats its values every \(\pi\) units.
- Behavior at Zero: For \(x = 0\), \(\tan x\) equals zero. This fact is significant when evaluating derivatives at \(x = 0\).
Higher Order Derivatives
Higher-order derivatives refer to derivatives of functions that are derived multiple times. In calculus, these are critical for understanding the intricate behavior of functions.
- First Derivative: For \(f(x) = \tan x\), the first derivative is \(f'(x) = \sec^2 x\). At \(x = 0\), it evaluates to 1 since \(\sec(0) = 1\).
- Second Derivative: The second derivative of \(\tan x\), \(f''(x) = 2 \tan x \sec^2 x\), simplifies to 0 at \(x = 0\) because \(\tan 0 = 0\).
- Subsequent Derivatives: For higher derivatives, the pattern often involves increasingly complex forms of trigonometric identities involving \(\tan x\) and \(\sec x\). These too simplify to 0 at \(x = 0\) because they contain terms like \(\tan 0\), which is zero.
Binomial Theorem
The Binomial Theorem is a powerful tool in algebra used to expand expressions that are raised to any power. It is succinctly expressed as:\[(a + b)^n = \sum_{k=0}^{n} { }^{n}C_{k} a^{n-k} b^k\]
- Binomial Coefficients: The terms \({ }^{n}C_k\) denote the binomial coefficients, calculated as \(\frac{n!}{k!(n-k)!}\), which determine the number of ways to choose \(k\) items from \(n\) without regard to the order.
- Expansion and Patterns: The theorem reveals a pattern of expanding polynomial expressions, which is crucial when working with expressions like those in our exercise.
- Application in Calculus: In calculus, integrating binomial expansions with derivative calculations allows for solving more complex problems involving higher-order derivatives and trigonometric functions.
Other exercises in this chapter
Problem 96
If \(u=\sin ^{-1} \frac{x}{y}+\tan ^{-1} \frac{y}{x}\), then \(x \frac{\partial u}{\partial x}+y \frac{\partial u}{\partial y}=\) (A) 0 (B) 1 (C) \(-1\) (D) Non
View solution Problem 98
If \(\cos ^{-1}\left(\frac{y}{b}\right)=\log \left(\frac{x}{n}\right)^{n}\), then \(x^{2} y_{n+2}+(2 n+1) x y_{n+1}\) \(+k y_{n}=0\) where \(k=\) (A) \(n^{2}\)
View solution Problem 100
If \(I_{n}=\frac{d^{n}}{d x^{n}}\left(x^{n} \log x\right)\), then \(I_{n}=n I_{n-1}+k\), where \(k=\) (A) \(n !\) (B) \((n-1) !\) (C) \((n-2) !\) (D) None of th
View solution Problem 102
\begin{tabular}{l} \hline \multicolumn{1}{c} { Column-I } \\ \hline I. The function \(y\) defined by the equa- \\ tion \(x y-\log y=1\) satisfies \(x\left(y y^{
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