Problem 99
Question
During reduction of carbonyl compounds by hydrazine and \(\mathrm{KOH}\), the first intermediate formed is (a) \(\mathrm{RCH}=\mathrm{NH}\) (b) \(\mathrm{RCONH}_{2}\) (c) \(\mathrm{RCH}=\mathrm{NNH}_{2}\) (d) \(\mathrm{RC} \equiv \mathrm{N}\)
Step-by-Step Solution
Verified Answer
The first intermediate formed is (c) \( \mathrm{RCH} = \mathrm{NNH}_2 \).
1Step 1: Understanding the Reaction
The reaction in question involves the reduction of carbonyl compounds using hydrazine and potassium hydroxide, commonly known as the Wolff-Kishner reduction. This reaction leads to the complete reduction of a carbonyl group to a methylene group.
2Step 2: Identifying the Mechanism
In the Wolff-Kishner reduction, the carbonyl compound reacts with hydrazine to form a hydrazone. This is the first intermediate formed in the reaction.
3Step 3: Structure of the Intermediate
The hydrazone intermediate is characterized by the structure \( \mathrm{RCH} = \mathrm{NNH}_2 \), where the carbonyl oxygen is replaced by \( \mathrm{NNH}_2 \). This happens after the elimination of water from the hydrazone formation.
4Step 4: Comparison with the Options
Now comparing the structures given in the options: \( \mathrm{RCH} = \mathrm{NNH}_2 \) matches exactly with option (c), which represents the hydrazone intermediate.
Key Concepts
Hydrazone IntermediateReduction of Carbonyl CompoundsMechanism of Wolff-Kishner Reaction
Hydrazone Intermediate
In the Wolff-Kishner reaction, the hydrazone intermediate plays a crucial role. This intermediate forms when a carbonyl compound reacts with hydrazine under basic conditions.
The structure of the hydrazone intermediate is represented by the equation: \[ \mathrm{RCH} = \mathrm{NNH}_2 \]Here, the carbonyl group's oxygen is replaced by the hydrazone moiety. This substitution happens through a condensation reaction, where water is eliminated as a by-product.
Creating this intermediate is a pivotal step in the reduction process, as it sets the stage for further transformation into a methylene group. Notably, the hydrazone is relatively stable, allowing it to undergo further reactions without decomposing prematurely.
The structure of the hydrazone intermediate is represented by the equation: \[ \mathrm{RCH} = \mathrm{NNH}_2 \]Here, the carbonyl group's oxygen is replaced by the hydrazone moiety. This substitution happens through a condensation reaction, where water is eliminated as a by-product.
Creating this intermediate is a pivotal step in the reduction process, as it sets the stage for further transformation into a methylene group. Notably, the hydrazone is relatively stable, allowing it to undergo further reactions without decomposing prematurely.
Reduction of Carbonyl Compounds
The Wolff-Kishner reduction is a technique for transforming carbonyl groups into methylene groups.
Carbonyl compounds typically contain a C=O bond, making them reactive and versatile in organic synthesis. However, in some cases, chemists need to reduce this bond entirely to achieve a fully saturated alkane product.
This makes it a powerful method in the toolbox of organic chemistry.
Carbonyl compounds typically contain a C=O bond, making them reactive and versatile in organic synthesis. However, in some cases, chemists need to reduce this bond entirely to achieve a fully saturated alkane product.
- By using hydrazine and a strong base such as potassium hydroxide, the Wolff-Kishner method effectively removes the oxygen.
- This leads to a total reduction without introducing additional reducing agents that could potentially be less selective or environmentally friendly.
This makes it a powerful method in the toolbox of organic chemistry.
Mechanism of Wolff-Kishner Reaction
Understanding the mechanism of the Wolff-Kishner reaction provides insight into how carbonyl compounds are reduced.
This reaction operates under basic conditions with hydrazine (NH₂NH₂). Initially, hydrazine reacts with the carbonyl compound, leading to the formation of the hydrazone intermediate. This is followed by:
Students studying this mechanism will appreciate how each step contributes to the transformation, making it more than just a simple conversion.
This reaction operates under basic conditions with hydrazine (NH₂NH₂). Initially, hydrazine reacts with the carbonyl compound, leading to the formation of the hydrazone intermediate. This is followed by:
- Base-induced deprotonation of the hydrazone at the α-carbon.
- The resulting anion undergoes a series of tautomerizations, culminating in nitrogen being released as nitrogen gas (N₂).
- This step drives the reaction forward, resulting in the complete reduction of the carbonyl compound to a methylene group (\(\mathrm{RCH}_2\)).
Students studying this mechanism will appreciate how each step contributes to the transformation, making it more than just a simple conversion.
Other exercises in this chapter
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